This is a much cleaner solution to the problem of allocating as much
working area as possible than what is currently being done in most/all flash
drivers (which is: try an arbitrary sized chunk, if it fails, pick a smaller
number, rinse and repeat).
Use this function to find out how much working area is available, limit or
restrict that amount at will and then simply allocate it.
Change-Id: Ib7d5d0b7485aed3e0a4fad60c1bedb7dfd16146f
Signed-off-by: Andreas Fritiofson <andreas.fritiofson@gmail.com>
Reviewed-on: http://openocd.zylin.com/446
Tested-by: jenkins
Reviewed-by: Spencer Oliver <spen@spen-soft.co.uk>
target_free_all_working_areas_restore(target, 1);
}
+/* Find the largest number of bytes that can be allocated */
+uint32_t target_get_working_area_avail(struct target *target)
+{
+ struct working_area *c = target->working_areas;
+ uint32_t max_size = 0;
+
+ if (c == NULL)
+ return target->working_area_size;
+
+ while (c) {
+ if (c->free && max_size < c->size)
+ max_size = c->size;
+
+ c = c->next;
+ }
+
+ return max_size;
+}
+
int target_arch_state(struct target *target)
{
int retval;
uint32_t size, struct working_area **area);
int target_free_working_area(struct target *target, struct working_area *area);
void target_free_all_working_areas(struct target *target);
+uint32_t target_get_working_area_avail(struct target *target);
extern struct target *all_targets;
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